{"id":20572,"date":"2020-07-30T22:52:42","date_gmt":"2020-07-31T05:52:42","guid":{"rendered":"https:\/\/careerkarma.com\/blog\/?p=20572"},"modified":"2023-12-01T03:57:10","modified_gmt":"2023-12-01T11:57:10","slug":"python-typeerror-int-object-is-not-iterable","status":"publish","type":"post","link":"https:\/\/careerkarma.com\/blog\/python-typeerror-int-object-is-not-iterable\/","title":{"rendered":"Python typeerror: \u2018int\u2019 object is not iterable Solution"},"content":{"rendered":"\n

Encountering an error is not a problem; it\u2019s a learning opportunity. While developing in Python, you may have seen an error \u201c\u2018int\u2019 object is not iterable\u201d.
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What does this mean? How do I solve it? Those are the questions we\u2019re going to answer in this article. We will discuss what the \u201c\u2018int\u2019 object is not iterable\u201d error is, why it is raised, and how you can solve it.<\/p>\n\n\n\n

The Problem: typeerror: \u2018int\u2019 object is not iterable<\/h2>\n\n\n\n

\u201ctypeerror: \u2018int\u2019 object is not iterable\u201d
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There are two parts to this error message: TypeError and the error message.
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A TypeError is raised when a function is applied to an object of the wrong data type. For instance, if you try to apply a mathematical function to a string, or call a value like a function which is not a function, a TypeError is raised.
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The error message tells us that you have tried to iterate over an object that is not iterable<\/a>. Iterable objects are items whose values you can access using a \u201cfor loop<\/a>\u201d.<\/p>\n\n\n\n

A Practice Scenario<\/h2>\n\n\n\n

One of the most common scenarios in which this error is raised is when you try to use a for loop with a number. This mistake is made because it’s easy to forget to use the range() function<\/a> when you are using a for loop.
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Consider the following code snippet:<\/p>\n\n\n\n

def count_occurrence(values, to_find):\n\tnumber_of_occurrences = 0\n\tfor v in len(values):\n\t\tif values[v] == to_find:\n\t\t\tnumber_of_occurrences += 1\n\treturn number_of_occurrences\n\nvalues = [1, 2, 3, 3]\ncheck_for_threes = count_occurrence(values, 3)\n\nprint(check_for_threes)<\/pre><\/div>\n\n\n\n
This code snippet uses one function. The count_occurance function counts how many times a number appears in the \u201cvalues\u201d list. This function iterates over all the values in \u201cvalues\u201d and keeps a running total of all those equal to a particular number. This number is specified as a parameter called \u201cto_find\u201d.
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In our main program, we define a list called \u201cvalues\u201d with four values. We call our count_occurrence function to count how many threes are in our list of values. We then print out the response to the console.
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Let\u2019s run our code:<\/p>\n\n\n\n
Traceback (most recent call last):\n  File "main.py", line 9, in <module>\n\tcheck_for_threes = count_occurrence(values, 3)\n  File "main.py", line 3, in count_occurrence\n\tfor v in len(values):\nTypeError: 'int' object is not iterable<\/pre><\/div>\n\n\n\n
Oh no! An error has been raised. Now that we\u2019ve replicated this error, we can solve it.<\/p>\n\n\n\n
The Solution<\/h2>\n\n\n\n
Our error tells us that we\u2019ve tried to iterate over an object that is not iterable. If we look at the error message in detail, we can see it points us to the line where the problem occurs:<\/p>\n\n\n\n
for v in len(values):<\/pre><\/div>\n\n\n\n
The problem with this line is that we are trying to iterate over a number.
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len(values) is equal to 4. That\u2019s how many values are in the list<\/a> \u201cvalues\u201d. If we try to iterate over a number, nothing happens. This is because for loops only work with iterable objects.
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To solve this problem, we need to make sure our for loop iterates over an iterable object. We can add a range()<\/code> statement to our code to do this:<\/p>\n\n\n\n
for v in range(len(values)):<\/pre><\/div>\n\n\n\n
This statement will create an iterable object with a list of values in the range of 0 and the number of items in the \u201cvalues\u201d list.
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Let\u2019s try to run our code again with the range()<\/code> statement. Our code returns:
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2<\/pre><\/div>\n\n\n\n
Our code has successfully found all the instances of 3 in the list. Our code has counted them all up and then printed the total number of times 3 appears in the list to the console.<\/p>\n\n\n\n