typeerror is thrown when a value is not of the expected type. Unlike the value of undefined, the null value can be unintentionally assigned a value developers code into their program. The error represents the absence of any value or object. The value is primitive and falsy.
The style property is used to get and set the inline style of a Document Object Model (DOM) element. DOM is a programming interface that represents the objects you see on a web page or document. You can manipulate this representation in the console.
In this article, we dive into the cause of receiving a typeerror of null when using the style property in the DOM, as well as some possible solutions.
getElements used when trying to manipulate an element on a web page or document.
document.getElementsByTagName('p') document.getElementsById('insertIdNameGivenToElement') document.getElementsByClassName('insertClassNameGivenToElement')
We can also use the
Let’s say that we have some of the following elements in the document we are trying to manipulate.
<h1 class="title"> Let's Fix This Error </h1> <ol class= "orderedList"> <li id="first"> First read the error message </li> <li id="second"> Second understand the error message </li> <li id="fourth"> Third, debug </li> </ol>
Let’s say we want to change the third item on the list. Using the DOM, the code should look something like this:
const changeDOM = document.getElementById('third'); changeDOM.style.color = 'green'
The error can also be thrown when misspelling values or ignoring the importance of case sensitivity.
<h1 class="title"> Let's Fix This Error </h1> <ol class= "orderedList"> <li id="first"> First read the error message </li> <li id="second"> Second understand the error message </li> <li id="third"> Third, debug </li> </ol> const changeDOM = document.getElementById('third'); changeDOM.style.color = 'green'
When trying to change the style of an element in the DOM, we have to make sure we are accessing it by the correct name. Any attempt to change the style of an element with an absent value will throw a typeerror value of null.